# The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7 mm, is 4.4 m/s. The period of oscillation is Option 1) 100 s Option 2) 0.01 s Option 3) 10 s Option 4) 0,1 s

As we learnt in

Relation of velocity and displacement -

- wherein

x is displacement from mean position

A is Amplitude.

:    Maximum velocity  $\nu _{m}= a\omega = a\left ( \frac{2\pi }{T} \right )$

$\therefore \: \: \: T= \frac{2\pi a}{\nu _{m}}= 2\times \frac{22}{7}\times \frac{\left ( 7\times 10^{-3} \right )}{4.4}$

$=10^{-2} sec= 0.01sec.$

Correct option is 2.

Option 1)

100 s

This is an incorrect option.

Option 2)

0.01 s

This is the correct option.

Option 3)

10 s

This is an incorrect option.

Option 4)

0,1 s

This is an incorrect option.

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