Q

# Help me understand! When a ball is thrown up vertically with velocity vo it reaches a maximum height of h. If one wishes to triple the maximum height then the ball should be thrown with velocity.

When a ball is thrown up vertically with velocity vo it reaches a maximum height of h. If one wishes to triple the maximum height then the ball should be thrown with velocity.

• Option 1)

vo√3

• Option 2)

3vo

• Option 3)

9vo

• Option 4)

(3/2)vo

254 Views

As we discussed in concept

Potential Energy -

$U_{f}-U_{i}= \int_{r_{i}}^{r_{f}}\vec{f}\cdot \vec{ds}$

- wherein

$U_{f}-final\: potential\: energy$

$U_{i}-initial \: potential\: energy$

$f-force$

$ds-small \: displacement$

$r_{i}-initial \: position$

$r_{f}-final\: position$

At Maximum height V=0

$V_{0}=\sqrt{2gh} ---(i)$

At  h1=3h

$u^{2}=2g(3h)=6gh$

$u=\sqrt{6gh} ---(ii)$

$\frac{V}{u}=\frac{\sqrt{2gh}}{\sqrt{6gh}}$

$=> u=\sqrt{3}V_{0}$

Option 1)

vo√3

Option is correct

Option 2)

3vo

Option is incorrect

Option 3)

9vo

Option is incorrect

Option 4)

(3/2)vo

Option is incorrect

Exams
Articles
Questions