Question

Asked in: JEE Main-2011

A 5.2 molal aqueous solution of methyl alcohol, CH3OH, is supplied. What is the mole fraction of methyl alcohol in the solution ?

A.

0.100

B.

0.190

C.

0.086

D.

0.050

Answers (1)

Molality = \frac{Moles \: of \: solute}{Mass \, \: o\! f\: solution(Kg)}

Mole Fraction -

\dpi{100} Mole\: Fraction= \frac{Moles\: o\! f\: solute}{Moles\: o\! f solute+Moles\: o\! f solvent}

 Let the Mass of water is 1 Kg so moles of CH3OH is 5.2

\chi_{solute}=\frac{5.2}{5.2+\frac{1000}{18}}=0.086

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