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How many different arrangements are possible for 9 examination papers if the top and lowest mark papers never appear together?

Option: 1

204340


Option: 2

220980


Option: 3

282240

 


Option: 4

302880


Answers (1)

best_answer

Given that,

There are 9 examination papers.

So, there are 9! Ways for 9 examination papers.

If the top and the lowest mark papers never appear together, then the number of ways is given by,

8!\times 2

Thus, the total number of ways is,

9!- 8!\times 2 = 362880-80640\\

9!- 8!\times 2 = 282240

Therefore, the number of ways in which the examination papers are arranged is 282240.

 

Posted by

Shailly goel

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