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How many different five-letter words starting with C can be formed using the letters A, B, C, D, E with and without repetition?

 

Option: 1

3125


Option: 2

2680


Option: 3

4690


Option: 4

5680


Answers (1)

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To calculate the number of different five-letter words starting with "C" that can be formed using the letters A, B, C, D, and E, we can use the concept of permutations.

Without repetition:

Since there are 5 available letters and we want to form a five-letter word, we start with 1 option for the first letter (which is "C" as it is specified), then we have 4 options for the second letter, 3 options for the third letter, 2 options for the fourth letter, and 1 option for the fifth letter.

The total number of different five-letter words starting with "C" and without repetition can be calculated as:

1 \times 4 \times 3 \times 2 \times 1=24

With repetition:

If repetition is allowed, then for each position in the five-letter word, we still have 5 options (A, B, C, D, E).

The total number of different five-letter words starting with "C" and with repetition can be calculated as:

5 \times 5 \times 5 \times 5 \times 5=3,125

Therefore, there are 24 different five-letter words starting with "C" without repetition, and 3,125 different five-letter words starting with "C" with repetition.

 

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