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  • How many different four-letter codes can be formed using the letters A, B, C, D, and E if repetition is allowed and the codes should have starting letter D?  <div class='qna-opti

How many different four-letter codes can be formed using the letters A, B, C, D, and E if repetition is allowed and the codes should have starting letter D?

 

Option: 1

125


Option: 2

150


Option: 3

100


Option: 4

200


Answers (1)

best_answer

If repetition is allowed and the codes should have the starting letter D, we can treat the starting letter as fixed and consider the remaining three positions.

For the second, third, and fourth positions, we have 5 choices (A, B, C, D, or E) since repetition is allowed.

Therefore, the total number of different four-letter codes with repetition allowed and starting letter D is calculated as:

1 (choice for the starting letter D) \times5 (choices for the second position) \times5 (choices for the third position)\times 5 (choices for the fourth position) = 1\times 5\times 5 \times5 = 125.

Hence, there are 125 different four-letter codes that can be formed using the letters A, B, C, D, and E, where repetition is allowed and the codes have the starting letter D.

 

Posted by

Kuldeep Maurya

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