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  • How many different nine digit numbers can be formed from the number 22  33 55 888 by rearranging its digits, so that the odd digits occupy even positions?  <div class='qna-option

How many different nine digit numbers can be formed from the number 22  33 55 888 by rearranging its digits, so that the odd digits occupy even positions?  

Option: 1

64


Option: 2

25


Option: 3

60


Option: 4

120


Answers (1)

best_answer
                 
1 2 3 4 5 6 7 8 9

Number of even places = 4

                     Odd digits = 3,3,5,5

Remaining digits on odd places = 2 2 8 8 8

\therefore Required number of ways =\frac{4 !}{2 ! 2 !} \times \frac{5 !}{2 ! 3 !}

                                               =60

Posted by

Deependra Verma

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