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How many different ways can a group of 10 people be divided into 2 teams, such that both teams contain 5 people each.

Option: 1

12


Option: 2

20


Option: 3

252


Option: 4

126


Answers (1)

best_answer

The given information is:

Number of people =10

Number of teams =2

Number of people in each team =5

Pick first 5 people from 10 people, 

Total no. of ways of choosing is:

\frac{10 !}{(10-5) ! 5 !}=\frac{10 !}{5 ! 5 !}=252

Pick last 5 people from 5 people and the number of ways this can be done is 1 .

Since the two groups are similar, there is no differentiation between them. Therefore, we

need to divide it with 2 !=2 .

The total numbers of ways:

\frac{252}{2}=126

Posted by

Sayak

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