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How many different ways can 20 Cricket players are divided into 2 teams of equal players for each team.

Option: 1

92370


Option: 2

92320


Option: 3

92378


Option: 4

92300


Answers (1)

best_answer

The given information is:

Number of players =20

Number of teams =2

Number of players in each team,

\frac{20}{2}=10  players

Pick first 10 players from 20 players, 

Total no. of ways of choosing is:

\frac{20 !}{(20-10) ! 10 !}=\frac{20 !}{10 ! 10 !}=184756

Pick last 10 players from remaining 10 players and the number of ways this can be done is 1 .

Since the four groups are similar, there is no differentiation between them. Therefore, we need to divide it with 2 !=2.

The total numbers of ways:

\frac{184756}{2}=92378

Posted by

Rakesh

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