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  • How many distinct six-digit numbers can be formed using the digits 1, 2, 3, 4, 5, and 6, where the middle digit must be odd?  <

How many distinct six-digit numbers can be formed using the digits 1, 2, 3, 4, 5, and 6, where the middle digit must be odd?

 

Option: 1

220


Option: 2

600


Option: 3

450


Option: 4

360


Answers (1)

best_answer

To find the number of distinct six-digit numbers that can be formed using the digits 1,2,3,4,5, and 6 , where the middle digit must be odd, we need to consider the possibilities for the positions of the digits.

Since the middle digit must be odd, there are 3 choices for the middle digit: 1,3 , or 5 . After choosing the middle digit, there are 5 remaining digits to choose from for the first position, 4 choices for the second position, 3 choices for the third position, 2 choices for the fourth position, and 1 choice for the fifth position.

Therefore, the total number of distinct six-digit numbers that can be formed, where the middle digit is odd, is

3 \times 5 \times 4 \times 3 \times 2 \times 1=360.

It is important to note that repetition is not allowed in this case, as the digits 1,2,3,4,5, and 6 are distinct.

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Anam Khan

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