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How many electrons would be required to deposit  \mathrm{12.7 g}  of copper at the cathode during the electrolysis of an aqueous solution of copper sulphate? 

Option: 1

0.3 NA


Option: 2

0.4 NA


Option: 3

0.6 NA


Option: 4

0.2 NA


Answers (1)

best_answer

\mathrm{Cu} \rightarrow \mathrm{Cu}^{++}+2 e
mole of al at cathode \rightarrow 2 moles of electron required

12.7 \mathrm{~g} \longrightarrow \frac{12.7}{63.5} \times 2 \\

=0.4 \mathrm{NA}.

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