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How many six-digit numbers are there in which no digit is repeated, even digits appear at even places, odd digits appear at odd places and the number is divisible by 4 ?

Option: 1

3600


Option: 2

2700


Option: 3

2160


Option: 4

1440


Answers (1)

best_answer

The number formed by last two digits must be divisible by 4.

3 ways 3 ways  4 ways 4 ways 5 ways 2 ways

                                                                      (1,3,5,7,9) (2,6)

3 \times 3 \times 4 \times 4 \times 5 \times 2=1440

Posted by

Sanket Gandhi

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