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  • How many ways are there to write a 4-digit positive integer using the digits 2, 3, 4, 6, and 8 if no digit is used more than once?  Opti

How many ways are there to write a 4-digit positive integer using the digits 2, 3, 4, 6, and 8 if no digit is used more than once?

 

Option: 1

120


Option: 2

180


Option: 3

360


Option: 4

480


Answers (1)

best_answer

Since we can choose from the five available digits, we have five options for the first digit. 

Similarly, because we have used up one of the digits, there are four options for the second digit and three options for the third digit. 

Again 2 options are available for the fourth digit.

So the total number of ways to write a 4-digit positive integer using the digits 2, 3, 4, 6, and 8 is,

\mathrm{ 5\times 4\times 3\times 2=120}

Therefore, there are 120 ways to write a 4-digit positive integer using the digits 2,3,4,6, ad 8 if no digit is used more than once.

 

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mansi

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