How much of NaOH is required to neutralise 1500 ml of 0.1 M HCl (Na = 23)
40 g
4 g
6 g
60 g
According to law of Equivalence,
meq. of HCl = meq. of NaOH
1500 0.1 = mmoles of NaOH (as n-factor of NaOH =1)
mmoles of NaOH = 150
Weight of NaOH = 6 g
Thus, the correct answer is Option (3)
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