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How much of NaOH is required to neutralise 1500 ml of 0.1 M HCl (Na = 23)

Option: 1

40 g


Option: 2

4 g


Option: 3

6 g


Option: 4

60 g


Answers (1)

best_answer

According to law of Equivalence,

meq. of HCl = meq. of NaOH

\therefore 1500 \times 0.1 = mmoles of NaOH (as n-factor of NaOH =1)

\therefore mmoles of NaOH = 150

\therefore Weight of NaOH = 6 g

Thus, the correct answer is Option (3)

Posted by

sudhir.kumar

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