A battery is used to charge a parallel plate capacitor till the potential difference between the plates becomes equal to the electromotive force of the battery. The ratio of the energy stored in the capacitor and the work done by the battery will be

  • Option 1)

    1/2

  • Option 2)

    1

  • Option 3)

    2

  • Option 4)

    1/4

 

Answers (2)

As we learnt in

Energy Stored -

U=\frac{1}{2}CV^{2}=\frac{1}{2}QV=\frac{Q^{2}}{2C}

-

 

 Let E be emf of the battery

Work done by the battery  W =CE2

Energy stored in the capacitor U= \frac{1}{2}CE^{2}

\therefore \: \: \: \frac{U}{W}= \frac{\frac{1}{2}CE^{2}}{CE^{2}}= \frac{1}{2}


Option 1)

1/2

Correct

Option 2)

1

Incorrect

Option 3)

2

Incorrect

Option 4)

1/4

Incorrect

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