# Get Answers to all your Questions

### Answers (2)

As we learnt in

Energy Stored -

-

The potential energy of a charged capacitor

$U_{i}= \frac{q^{2}}{2C}$

where $U_{i}$ is the initial potential energy. If a dielectric slab is slowly introduced, the energy

$= \frac{q^{2}}{2KC}$

Once is taken out, again the energy increases to the old value. Therefore after it is taken out, the potential energy come back to the old value.

Total work done =ZERO

Option 1)

ZERO

Correct

Option 2)

Incorrect

Option 3)

Incorrect

Option 4)

Incorrect

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