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  • How to solve this problem- A progress wave gets reflected at a boundary such that the ratio of amplitudes of reflected & Incident wave is 1:2, find the percentage of energy transmitted.

A progress wave gets reflected at a boundary such that the ratio of amplitudes of reflected & Incident wave is 1:2, find the percentage of energy transmitted.

  • Option 1)

    25%

  • Option 2)

    75%

  • Option 3)

    50%

  • Option 4)

    80%

 

Answers (1)

best_answer

\frac{A_{r}}{A_{i}}= \frac{1}{2} \Rightarrow \frac{I_{1}}{I_{2}} = (\frac{1}{2})^{2}

E_{1 }= 1- (\frac{1}{2})^{2}= \frac{3}{4}

E= \frac{3}{4}\times 100= 75 %

 

Amplitude of reflected wave -

A_{r}= \frac{\left ( V_{2}-V_{1} \right )A_{i}}{\left ( V_{2}+V_{1} \right )}

A_{r}= amplitude of reflected wave

- wherein

 

V_{1}\; and \; V_{2} are velocity of wave in incident and transmitted wave.

A_{i}= amplitude of incident  wave.

 

 

 


Option 1)

25%

This is incorrect

Option 2)

75%

This is correct

Option 3)

50%

This is incorrect

Option 4)

80%

This is incorrect

Posted by

Aadil

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