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  • How to solve this problem- A transformer consisting of 300 turns in the primary and 150 turns in secondarygives output power of 2.2 kW. If the current in the secondary coil is 10A, then theinput voltage and current in the primary coil are:

A transformer consisting of 300 turns in the primary and 150 turns in secondary 

gives output power of 2.2 kW. If the current in the secondary coil is 10A, then the 

input voltage and current in the primary coil are:

  • Option 1)

    220 V and 20 A 

  • Option 2)

    440 V and 20 A

  • Option 3)

    440 V and 5 A

  • Option 4)

     220 V and 10 A

 

Answers (1)

best_answer

 

Ideal transformer -

There is no loss of power.

- wherein

P_{out}= P_{in}

V_{s}\, {i}'_{s}= V_{in}i_{in}

 

 

Ideal transformer -

\frac{\varepsilon _{s}}{\varepsilon _{P}}= \frac{N _{s}}{N _{P}}= \frac{V_{s}}{V _{P}}= \frac{{i}' _{P}}{{i}'_{s}}
 

- wherein

\varepsilon _{s}\rightarrow induced e.m.s.in secondary

\varepsilon _{P}\rightarrow induced e.m.s.in primary

 

 

P_{out}=V_oI_o

P_{out}=2.2kW

=> 2.2kW=V_o\times 10

=> V_o=\frac{2.2\times 10^{3}}{10}=220V

Now,

\frac{n_I}{n_{II}}=\frac{V_I}{V_{II}}=\frac{I_{II}}{I_I}

So, \frac{300}{150}=\frac{V_I}{220}

=> V_I=440V

Similarly,

\frac{300}{150}=\frac{I_{II}}{I_{I}}

I_{I}=\frac{I_{II}}{2}=\frac{10}{2}=5A


Option 1)

220 V and 20 A 

Option 2)

440 V and 20 A

Option 3)

440 V and 5 A

Option 4)

 220 V and 10 A

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