# A transformer consisting of 300 turns in the primary and 150 turns in secondary gives output power of 2.2 kW. If the current in the secondary coil is 10A, then the input voltage and current in the primary coil are: Option 1) 220 V and 20 A  Option 2) 440 V and 20 A Option 3) 440 V and 5 A Option 4)  220 V and 10 A

Ideal transformer -

There is no loss of power.

- wherein

$P_{out}= P_{in}$

$V_{s}\, {i}'_{s}= V_{in}i_{in}$

Ideal transformer -

$\frac{\varepsilon _{s}}{\varepsilon _{P}}= \frac{N _{s}}{N _{P}}= \frac{V_{s}}{V _{P}}= \frac{{i}' _{P}}{{i}'_{s}}$

- wherein

$\varepsilon _{s}\rightarrow$ induced e.m.s.in secondary

$\varepsilon _{P}\rightarrow$ induced e.m.s.in primary

$P_{out}=V_oI_o$

$P_{out}=2.2kW$

=> $2.2kW=V_o\times 10$

=> $V_o=\frac{2.2\times 10^{3}}{10}=220V$

Now,

$\frac{n_I}{n_{II}}=\frac{V_I}{V_{II}}=\frac{I_{II}}{I_I}$

So, $\frac{300}{150}=\frac{V_I}{220}$

=> $V_I=440V$

Similarly,

$\frac{300}{150}=\frac{I_{II}}{I_{I}}$

$I_{I}=\frac{I_{II}}{2}=\frac{10}{2}=5A$

Option 1)

220 V and 20 A

Option 2)

440 V and 20 A

Option 3)

440 V and 5 A

Option 4)

220 V and 10 A

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