Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • How to solve this problem- A wire suspended vertically from one of its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm. Then the elastic energy stored in the wire is

A wire suspended vertically from one of its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm. Then the elastic energy stored in the wire is

  • Option 1)

    0.2\: J

  • Option 2)

    10\: J

  • Option 3)

    20\: J

  • Option 4)

    0.1\: J

 

Answers (2)

best_answer

As we learnt in

Work Done in Stretching Wire / Elastic P.E. -

=\frac{1}{2}\frac{YAl^{2}}{L}=\frac{1}{2}Fl

- wherein

L - Length of wire

l - increase in length

 

 We know that 

E=\frac{1}{2}\times F\times \Delta l

=\frac{1}{2}\times 200\times 10^{-3}J=0.1\ J

Correct option is 4.


Option 1)

0.2\: J

This is an incorrect option.

Option 2)

10\: J

This is an incorrect option.

Option 3)

20\: J

This is an incorrect option.

Option 4)

0.1\: J

This is the correct option.

Posted by

perimeter

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Option 1- 0.2j

 

Posted by

Subham

View full answer

Similar Questions

Trending Articles/News

anam-khan

BTech Admission 2025 Live: JEE Mains, SRMJEEE, MET registrations underway; MHT CET syllabus updates
anam-khan

Centre issues coaching guidelines, prohibits centres from using false claims like '100% selection'
anam-khan

BTech Admissions 2025 Live: JEE Mains, SRMJEE, VITEEE dates out; AEEE, MET registrations underway

Latest Question