Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Tangent and normal are drawn at P(16, 16) on the parabola $y$ ²=16 $x$ , which
intersect the axis of the parabola at A and B, respectively. If C is the centre of the
circle through the points P, A and B and $\angle$ CPB=θ, then a value of tan θ is :

Option 1)
$\frac{4}{3}$

Option 2)
$\frac{1}{2}$

Option 3)
$2$

Option 4)
$3$

Answers (1)

best_answer

Equation of AP $T= 0$

$16y = \frac{16}{2}\left ( x+16 \right )$

$x- 2y + 16 = 0$

slope = 1/2

put $y= 0, x = -16$

equation of normal

$y-16 = -2\left ( x-16 \right )$

put $y=0 , x= 24$

$m_{pc}= 4/3$

$m_{pb}= -2$

$\tan \theta = 2$

Equation of tangent -

$yy_{1}= 2a\left ( x+x_{1} \right )$

- wherein

Tangent at $P\left ( x,y_{1} \right )on$ $y^{2}=4ax$

Option 1)

$\frac{4}{3}$

Option 2)

$\frac{1}{2}$

Option 3)

$2$

Option 4)

$3$

Posted by

Himanshu

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Result 2024 Live: JEE Mains session 2 results at jeemain.nta.ac.in soon; rank predictor

anam-khan

JEE Main 2024 session 2 final answer key out at jeemain.nta.ac.in; steps to check probable scores

anam-khan

JEE Main Result 2024 Live: Download session 2 final answer key at jeemain.nta.ac.in; rank predictor, cutoff

Latest Question