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  • How to solve this problem- - Complex numbers and quadratic equations - JEE Main-4

Let z= \left ( x-1 \right )+\left ( y-2 \right )i,  if   \left | z \right |= 0  then  x+y equals \left ( Where\; x,y\, \epsilon \, R \right )

  • Option 1)

    1

  • Option 2)

    2

  • Option 3)

    3

  • Option 4)

    4

 

Answers (1)

\because \left | z \right |=0 , it is possible when z = 0

\Rightarrow \left ( x-1 \right )+\left ( y-2 \right )i=0

\Rightarrow x=1\: and\: y=2

So, x+y=3

\therefore Option (C)

 

Property of Modulus of z(Complex Number) -

|z|=0 iff z=0

- wherein

|z|= Modulus of z

 

 


Option 1)

1

This is incorrect

Option 2)

2

This is incorrect

Option 3)

3

This is correct

Option 4)

4

This is incorrect

Posted by

Vakul

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