In an optics experiment, with the position of the object fixed, a student varies the position of a convex lens and for each position, the screen is adjusted to get a clear image of the object. A graph between the object distance and the image distance , from  the lens, is plotted using the same scale for the two axes. A straight line passing through the origin and making an angle of with the meets the experimental curve at . The coordinates of will  be Option 1) Option 2) Option 3) Option 4)

As we learnt in

To find the focal length of a conclave lens using convex lens -

f= focal lenght of conclave lens L2

u= distance of I from optical centre

v=  distance of I from optical centre of lens L2

- wherein

Calculation

Result

Focal lenght of the given conclave lens I

f = mean focal lenght

We have

Apply cartesian sign convention

V is +ve and u is -ve

Since the straight line makes an angle of

We have V=U at P and each must be equal to 2f to satisfy eqn.

Option 1)

This option is correct

Option 2)

This option is incorrect

Option 3)

This option is incorrect

Option 4)

This option is incorrect

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