In an optics experiment, with the position of the object fixed, a student varies the position of a convex lens and for each position, the screen is adjusted to get a clear image of the object. A graph between the object distance and the image distance , from the lens, is plotted using the same scale for the two axes. A straight line passing through the origin and making an angle of with the meets the experimental curve at . The coordinates of will be
As we learnt in
To find the focal length of a conclave lens using convex lens -
f= focal lenght of conclave lens L2
u= distance of I from optical centre
v= distance of I from optical centre of lens L2
- wherein
Calculation
Result
Focal lenght of the given conclave lens I
f = mean focal lenght
We have
Apply cartesian sign convention
V is +ve and u is -ve
Since the straight line makes an angle of
We have V=U at P and each must be equal to 2f to satisfy eqn.
So 2f is the answer
Option 1)
This option is correct
Option 2)
This option is incorrect
Option 3)
This option is incorrect
Option 4)
This option is incorrect
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