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In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. The percentage of Bromine in the compound is 

  • Option 1)

    34.04

  • Option 2)

    60

  • Option 3)

    30

  • Option 4)

    20

 

Answers (1)

best_answer

As we discussed in concept

Carius method test for halogens -

percentage\:of\:X=\frac{Atomic\:mass\times m_{1}\times 100}{molecular\:mass\:of\:AgX\times m}

- wherein

 

 Carius method is used for the estimation of halogen

\%\:of\:Br\:=\: \frac{80 \times m_1 \times 100}{188 \times m}

                   =\: \frac{80 \times 0.12 \times 100}{188 \times 0.15}

                   = 34.04 g

 


Option 1)

34.04

This option is correct.

Option 2)

60

This option is incorrect.

Option 3)

30

This option is incorrect.

Option 4)

20

This option is incorrect.

Posted by

prateek

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