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  • How to solve this problem- In Quick's Tube the sound intensity being detected changes from max to min for 2nd time, when the slidable tube is drawn apart by 9.0 cm. If speed of air 336 m/s, then frequency of their sounding source

In Quick's Tube the sound intensity being detected changes from max to min for 2nd time, when the slidable tube is drawn apart by 9.0 cm. If speed of air 336 m/s, then frequency of their sounding source

  • Option 1)

    2.8 kHz

  • Option 2)

    2.3 kHz

  • Option 3)

    2 kHz

  • Option 4)

    1 kHz

 

Answers (1)

best_answer

Total path diff=\frac{\lambda }{2}+\lambda =\frac{3\lambda }{2}

\frac{3\lambda }{2}=18cm

\lambda =12cm

f=\frac{v}{\lambda }=\frac{336}{12\times 10^{-2}}=2.8KHz

 

Quinck's tube -

This is an apparatus used to demonstrate the phenomena of interferance and also used to measure velocity of sound in air.

- wherein

x= \frac{\lambda }{2}

V=2\nu _{0}x

\nu _{0}= frequency

 

 


Option 1)

2.8 kHz

This is correct

Option 2)

2.3 kHz

This is incorrect

Option 3)

2 kHz

This is incorrect

Option 4)

1 kHz

This is incorrect

Posted by

divya.saini

View full answer

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