In the circuit below, identify the equivalent gate

  • Option 1)

    OR

  • Option 2)

    AND

  • Option 3)

    NOR

  • Option 4)

    NAND

 

Answers (1)

As we learnt in 

AND Gate -

Y= A\cdot B

- wherein

A and B are input

Y is out put

 X=\bar{A}+\bar{B}

Y=\bar{X}= \overline {\Bar{A}+ \Bar {B}} = \bar{\bar{A}}-\bar{\bar{B}} (using D'morgan\: law)

Y=A . B

This represent AND gate.

 


Option 1)

OR

This option is incorrect.

Option 2)

AND

This option is correct.

Option 3)

NOR

This option is incorrect.

Option 4)

NAND

This option is incorrect.

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