Q

How to solve this problem- In the circuit shown in figure, the heat produced in 5 ohm resistance is 10 calories per second. The heat produced in 4 resistance is

In the circuit shown in figure, the heat produced in 5 ohm resistance is 10 calories per second. The heat produced in 4 resistance is

• Option 1)

1 cal/sec

• Option 2)

2 cal/sec

• Option 3)

3 cal/sec

• Option 4)

4 cal/sec

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As we learnt in

Current through any resistance -

$i'=i(\frac{Resistance\, of \, opposite \, Branch}{total\, Resistance})$

- wherein

Let current through $5\Omega$ be I1 and current through $4\Omega$ be I2 .

Then,

$I_{2}= I_{1}\left ( \frac{5}{6+4} \right )=\frac{I_{1}}{2}$

$P_{1} = \left ( I_{1}^{2} \right ) 5= 10\ cal/sec$

$P_{2} = I_{2}^{2} \times 4= \frac{I_{1}^{2}}{4}\times 4 =I_{1}^{2} = 2 \ cal/sec$

Option 1)

1 cal/sec

This option is incorrect

Option 2)

2 cal/sec

This option is correct

Option 3)

3 cal/sec

This option is incorrect

Option 4)

4 cal/sec

This option is incorrect

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