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  • How to solve this problem- In the circuit shown in figure, the heat produced in 5 ohm resistance is 10 calories per second. The heat produced in 4 resistance is

In the circuit shown in figure, the heat produced in 5 ohm resistance is 10 calories per second. The heat produced in 4 resistance is

 

  • Option 1)

    1 cal/sec

  • Option 2)

    2 cal/sec

  • Option 3)

    3 cal/sec

  • Option 4)

    4 cal/sec

 

Answers (1)

best_answer

As we learnt in

Current through any resistance -

i'=i(\frac{Resistance\, of \, opposite \, Branch}{total\, Resistance})

- wherein

 

Let current through 5\Omega be I1 and current through 4\Omega be I2 .

Then, 

I_{2}= I_{1}\left ( \frac{5}{6+4} \right )=\frac{I_{1}}{2}

P_{1} = \left ( I_{1}^{2} \right ) 5= 10\ cal/sec

P_{2} = I_{2}^{2} \times 4= \frac{I_{1}^{2}}{4}\times 4 =I_{1}^{2} = 2 \ cal/sec


Option 1)

1 cal/sec

This option is incorrect

Option 2)

2 cal/sec

This option is correct

Option 3)

3 cal/sec

This option is incorrect

Option 4)

4 cal/sec

This option is incorrect

Posted by

prateek

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