Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • How to solve this problem- In which of the following arrangements, the sequence is not strictly according to the property written against it ?

In which of the following arrangements, the sequence is not strictly according to the property written against it ?

  • Option 1)

    CO_{2}< SiO_{2}< SnO_{2}< PbO_{2}: increasing oxidising power

  • Option 2)

    HF< HCl< HBr< HI:increasing acid strength

  • Option 3)

    NH_{3}< PH_{3}< AsH_{3}< SbH_{3} increasing basic strength

  • Option 4)

    B< C< O< N increasing first ionization enthalpy

 

Answers (1)

best_answer

As we learnt in

Reducing power of Hydride -

HI>HBr>HCl>HF

Increases down the group 

 

 As we move down the group, the acidic strength of hydrides increases. So, option 3 is incorrect.


Option 1)

CO_{2}< SiO_{2}< SnO_{2}< PbO_{2}: increasing oxidising power

This option is incorrect.

Option 2)

HF< HCl< HBr< HI:increasing acid strength

This option is incorrect.

Option 3)

NH_{3}< PH_{3}< AsH_{3}< SbH_{3} increasing basic strength

This option is correct.

Option 4)

B< C< O< N increasing first ionization enthalpy

This option is incorrect.

Posted by

Plabita

View full answer

Crack JEE Main with "AI Coach"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
jee_ads

Similar Questions

Trending Articles/News

anam-khan

JEE Main Cut Off 2023: NIT closing ranks for BTech electrical engineering
anam-khan

JEE Main 2023: IIT, NIT cut-off marks for BTech in artificial intelligence
anam-khan

JEE Main 2023 session 2 registration last date today; apply at jeemain.nta.nic.in

Latest Question