In which of the following arrangements, the sequence is not strictly according to the property written against it ?

  • Option 1)

    CO_{2}< SiO_{2}< SnO_{2}< PbO_{2}: increasing oxidising power

  • Option 2)

    HF< HCl< HBr< HI:increasing acid strength

  • Option 3)

    NH_{3}< PH_{3}< AsH_{3}< SbH_{3} increasing basic strength

  • Option 4)

    B< C< O< N increasing first ionization enthalpy

 

Answers (1)

As we learnt in

Reducing power of Hydride -

HI>HBr>HCl>HF

Increases down the group 

 

 As we move down the group, the acidic strength of hydrides increases. So, option 3 is incorrect.


Option 1)

CO_{2}< SiO_{2}< SnO_{2}< PbO_{2}: increasing oxidising power

This option is incorrect.

Option 2)

HF< HCl< HBr< HI:increasing acid strength

This option is incorrect.

Option 3)

NH_{3}< PH_{3}< AsH_{3}< SbH_{3} increasing basic strength

This option is correct.

Option 4)

B< C< O< N increasing first ionization enthalpy

This option is incorrect.

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