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A block is kept on a frictionless inclined surface with angle of inclination \alpha. The incline is given  an  acceleration  a to  keep the block stationary. then a is equal to

  • Option 1)

    g

  • Option 2)

    g\tan \alpha

  • Option 3)

    g/\tan \alpha

  • Option 4)

    g\: cosec \: \alpha

 

Answers (1)

best_answer

As we learnt in

Non Inertial Frame of Reference -

Accelerated frames are Non Inertial.

Examples- car moving with uniform circular motion, plane which is taking off.

- wherein

Newton's law are not valid 

\vec a\neq0,      if \vec{F}= 0

\ast pseudo \left ( -m\vec{a} \right ) act on the body.

- means direction opposite  

 

 

The incline is given an acceleration . a  Acceleration of the block is to the right.  Pseudo   acceleration  a  acts on block to the left Equate   resolved parts of a and g  along incline.

\therefore ma\: \cos \alpha = mg\sin \alpha

or \: \: \: a= g\tan \alpha

Correct option is 2.

 


Option 1)

g

This is an incorrect option.

Option 2)

g\tan \alpha

This is the correct option.

Option 3)

g/\tan \alpha

This is an incorrect option.

Option 4)

g\: cosec \: \alpha

This is an incorrect option.

Posted by

prateek

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