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  • How to solve this problem- - Oscillations and Waves - JEE Main-7

The equation of the wave is given by y = 0.5\sin(100t +25x). The ratio of maximum particle velocity to wave velocity is

  • Option 1)

    12.5

  • Option 2)

    25

  • Option 3)

    4

  • Option 4)

    \frac{1}8

 

Answers (1)

best_answer

{v_{p(max)}} = \left ( \frac{dy}{dt} \right )_{max} = 50

v_{w} = \frac{\omega }{k} = \frac{100}{25} = 4

\frac{v_{p(max)}}{v_{w}} = 12.5

 

Relation between phase velocity and wave speed -

V_{P}= -V\: \frac{dy}{dx}

- wherein

V_{P}= particle velocity

V = wave velocity

\frac{dy}{dx}= slope of curve

 

 

 


Option 1)

12.5

This is correct.

Option 2)

25

This is incorrect.

Option 3)

4

This is incorrect.

Option 4)

\frac{1}8

This is incorrect.

Posted by

Avinash

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