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  • How to solve this problem- The average kinetic energy (in joules of) molecules in 8.0 g of Methane at 27º C is :

 The average kinetic energy (in joules of) molecules in 8.0 g of Methane at 27º C is :

  • Option 1)

     6.21 \times 10-20 J/molecule

  • Option 2)

     6.21 \times 10-21 J/molecule

  • Option 3)

     6.21 \times 10-22 J/molecule

  • Option 4)

    3.1 \times 10-22 J/molecule

 

Answers (1)

best_answer

As we learnt in 

Kinetic Theory of Gases -

Though the individual speeds are changing, the distribution of speeds remains constant at a particular temperature.

-

 

Average\: KE = \frac{3}{2}\times \frac{8.314\times 300}{6.023 \times 10^{23} }= 6.21 \times 10^{-21}\: J/molecule.


Option 1)

 6.21 \times 10-20 J/molecule

Incorrect

Option 2)

 6.21 \times 10-21 J/molecule

Correct

Option 3)

 6.21 \times 10-22 J/molecule

Incorrect

Option 4)

3.1 \times 10-22 J/molecule

Incorrect

Posted by

divya.saini

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