the highest magnetic moment for transition metal exists for

  • Option 1)

    3d^{9}

  • Option 2)

    3d^{7}

  • Option 3)

    3d^{5}

  • Option 4)

    3d^{3}

 

Answers (1)

As we learnt in 

Calculation of spin only magnetic moment -

\mu =\sqrt{n(n+2)}

\mu =magnetic\:moment\:in(BM)

where n = no. of unpaired electron 

n=1......5(no.\:of\:unpaired\:e^{-})

- wherein

V^{2+}\rightarrow3d^{3}=\sqrt{3(3+2)}

=\sqrt{15}

=3.87\:\:\:BM

3+.9\rightarrow 3.9(BM)

 

 \mu = \sqrt{ n\left ( n+2 \right )}

\mu = magnetic\:\: moment

n = Number of unpaired electrons

Therefore, maximum unpaired electrons give highest magnetic moment.

3dhas 5 unpaired electrons, higher than any other species. 

 

 

 

 

 

 

 

 


Option 1)

3d^{9}

This answer option is incorrect

Option 2)

3d^{7}

This answer option is incorrect

Option 3)

3d^{5}

This answer option is correct

Option 4)

3d^{3}

This answer option is incorrect

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