Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • How to solve this problem- The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (If its second's pendulum on earth)

The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (If its second's pendulum on earth)

  • Option 1)

    \frac{1}{\sqrt{2}}\;s

  • Option 2)

    2\sqrt{2}\;s

  • Option 3)

    2 \;s

  • Option 4)

    \frac{1}{}2 \;s

 

Answers (1)

best_answer

As we know   g = \frac{GM}{R^{2}}

\Rightarrow \frac{g_{earth}}{g_{planet}} =\frac{M_{e}}{M_{p}} \times \frac{R_{p}^{2}}{R_{e}^{2}} \Rightarrow \frac{g_{earth}}{g_{planet}} = 2

Also,

 T\;\alpha\;\frac{1}{\sqrt{g}} \Rightarrow \frac{T_{e}}{T_{p}} = \sqrt{\frac{g_{p}}{g_{e}}} \Rightarrow \frac{2}{T_{p}} =\sqrt{\frac{1}{2}} \\*\Rightarrow T_{p} = 2\sqrt{2}s

 

Time period of a ball through tunnel in earth -

T= 2\pi \sqrt{\frac{R}{g}}\\=84.6\: min

- wherein

R= Radius of earth

g= acceleration due to gravity

 

 

 


Option 1)

\frac{1}{\sqrt{2}}\;s

This is incorrect.

Option 2)

2\sqrt{2}\;s

This is correct.

Option 3)

2 \;s

This is incorrect.

Option 4)

\frac{1}{}2 \;s

This is incorrect.

Posted by

divya.saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question