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- How to solve this problem- When a radioactive isotope 88Ra228 decays in series by the emission of three α-particles and a β particle the isotope finally formed is :
When a radioactive isotope 88Ra228 decays in series by the emission of three α-particles and a β particle the isotope finally formed is :
- Option 1)
- Option 2)
- Option 3)
- Option 4)
Answers (1)
As learnt in
? -decay -
- wherein
Option 1)
This option is incorrect
Option 2)
This option is incorrect
Option 3)
This option is correct
Option 4)
This option is incorrect
View full answer
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