When a radioactive isotope 88Ra228 decays in series by the emission of three α-particles and a β particle the isotope finally formed is :

 

  • Option 1)

    _{84}X^{220}

  • Option 2)

    _{86}X^{222}

  • Option 3)

    _{83}X^{216}

  • Option 4)

    _{83}X^{215}

 

Answers (1)

As learnt in

? -decay -

^{A}_{Z}X\rightarrow ^{A-4}_{Z-2}Y+^{4}_{2}He+Q

 

- wherein

Q\: value = \left ( M_{X} -M_{Y}-M_{He}\right )c^{2}

 

 


Option 1)

_{84}X^{220}

This option is incorrect

Option 2)

_{86}X^{222}

This option is incorrect

Option 3)

_{83}X^{216}

This option is correct

Option 4)

_{83}X^{215}

This option is incorrect

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