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  • I have a doubt, kindly clarify. A compound exists in the gaseous phase both as monomer (A) and dimer (A2). The atomic mass of A is 48 and molecular mass of A2 is 96. In an experiment 96 g of the compound was confined in a vessel of volume 33.6 litre

 A compound exists in the gaseous phase both as monomer (A) and dimer (A2). The atomic mass of A is 48 and molecular mass of A2 is 96. In an experiment 96 g of the compound was confined in a vessel of volume 33.6 litre and heated to 273ºC. The pressure developed if the compound exists as dimer to the extent of 50 % by weight under these conditions will be :

  • Option 1)

    1 atm

  • Option 2)

    2 atm

  • Option 3)

    1.5 atm

  • Option 4)

    4 atm

 

Answers (1)

best_answer

As we learnt in 

Partial Pressure of a gas in gaseous mixture -

Partial Pressure = (Total Pressure of Mixture) \times (mole fraction of gas)

 

-

Since A and A2 are two states in gaseous phase having their wt ratio 50% i.e. 1 : 1

moles \: o\! f\: A = \frac{96}{2}\times \frac{1}{48}= 1

moles \: o\! f\: A _{2}= \frac{96}{2}\times \frac{1}{96}= \frac{1}{2}

Total \: moles = 3/2

P = nRT/V = 2 atm

 

 

 


Option 1)

1 atm

Incorrect

Option 2)

2 atm

Correct

Option 3)

1.5 atm

Incorrect

Option 4)

4 atm

Incorrect

Posted by

Plabita

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