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  • I have a doubt, kindly clarify. A metal crystallises with a FCC lattice. THe edge length pf unit cell is 408 pm. The diameter of metal atom is

A metal crystallises with a FCC lattice. THe edge length pf unit cell is 408 pm. The diameter of metal atom is

  • Option 1)

    288 pm

  • Option 2)

    408 pm

  • Option 3)

    144 pm

  • Option 4)

    204 pm

 

Answers (1)

best_answer

For FCC lattice 4r=a\sqrt{2}

                         r=\frac{a\sqrt{2}}{4}=\frac{408}{2\sqrt{2}}=144pm

                    diameter=2r=144\times 2=288pm

 

Relation between radius of constituent particle, r and edge length, a for face centered cubic unit cell -

Image result for Relation between radius of constituent particle, r and edge length, a for face centered cubic unit cell

      AB^{2}=b^{2}=a^{2}+a^{2}.

                 b=4r.

             a=2\sqrt{2}r.

           

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Option 1)

288 pm

This is correct

Option 2)

408 pm

This is incorrect

Option 3)

144 pm

This is incorrect

Option 4)

204 pm

This is incorrect

Posted by

divya.saini

View full answer

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