Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • I have a doubt, kindly clarify. A second's pendulum is placed in a space laboratory orbiting around the earth at a height 3R, where R is the radius of the earth. The time period of the pendulum is

A second's pendulum is placed in a space laboratory orbiting around the earth at a height 3R, where R is the radius of the earth. The time period of the pendulum is 

  • Option 1)

    Zero

  • Option 2)

    2\sqrt{3} s

  • Option 3)

    4 s

  • Option 4)

    Infinte

 

Answers (1)

best_answer

In the given effective acceleration g_{eff} = 0\Rightarrow T = \infty

 

Time period of pendulum of large length but small amplitude -

T= 2\pi \sqrt{\frac{1}{g\left ( \frac{1}{l}+\frac{1}{R} \right )}}

- wherein

l= length of pendulum

g= acceleration due to gravity.

R= Radius of earth

 

 

 


Option 1)

Zero

This is incorrect.

Option 2)

2\sqrt{3} s

This is incorrect.

Option 3)

4 s

This is incorrect.

Option 4)

Infinte

This is correct.

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question