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A second's pendulum is placed in a space laboratory orbiting around the earth at a height 3R, where R is the radius of the earth. The time period of the pendulum is 

  • Option 1)

    Zero

  • Option 2)

    2\sqrt{3} s

  • Option 3)

    4 s

  • Option 4)

    Infinte

 

Answers (1)

best_answer

In the given effective acceleration g_{eff} = 0\Rightarrow T = \infty

 

Time period of pendulum of large length but small amplitude -

T= 2\pi \sqrt{\frac{1}{g\left ( \frac{1}{l}+\frac{1}{R} \right )}}

- wherein

l= length of pendulum

g= acceleration due to gravity.

R= Radius of earth

 

 

 


Option 1)

Zero

This is incorrect.

Option 2)

2\sqrt{3} s

This is incorrect.

Option 3)

4 s

This is incorrect.

Option 4)

Infinte

This is correct.

Posted by

Aadil

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