A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be :
92 ± 2 s
92 ± 5.0 s
92 ± 1.8 s
92 ± 3 s
As we learnt in
Time period of oscillation of simple pendulum -
- wherein
l = length of pendulum
g = acceleration due to gravity.
Sum of all observation = 90 + 91 + 95 + 92 = 368
Average
Sum of modulus observations = 2 + 1 + 3 = 6
Average error , rounded of 2.
Final answer
Correct option is 1.
Option 1)
92 ± 2 s
This is the correct option.
Option 2)
92 ± 5.0 s
This is an incorrect option.
Option 3)
92 ± 1.8 s
This is an incorrect option.
Option 4)
92 ± 3 s
This is an incorrect option.
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