# A student measures the time period of 100 oscillations of a simple pendulum four times.  The data set is 90 s, 91 s, 95 s and 92 s.  If the minimum division in the measuring clock is 1 s, then the reported mean time should be : Option 1) 92 ± 2 s Option 2) 92 ± 5.0 s Option 3) 92 ± 1.8 s Option 4) 92 ± 3 s

As we learnt in

Time period of oscillation of simple pendulum -

- wherein

l = length of pendulum

g = acceleration due to gravity.

Sum of all observation = 90 + 91 + 95 + 92 = 368

Average

Sum of modulus observations = 2 + 1 + 3 = 6

Average error ,  rounded of 2.

Correct option is 1.

Option 1)

92 ± 2 s

This is the correct option.

Option 2)

92 ± 5.0 s

This is an incorrect option.

Option 3)

92 ± 1.8 s

This is an incorrect option.

Option 4)

92 ± 3 s

This is an incorrect option.

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