# Consider the ground state of Cr atom $\dpi{100} \left ( Z=24 \right )$.The numbers of electrons with the azimuthal quantum numbers $\dpi{100} l= 1\: and\: 2$ are, respectively Option 1) $12 \: and \: 4$ Option 2) $12 \: and \: 5$ Option 3) $16 \: and \: 4$ Option 4) $16 \: and \: 5$

As we learnt in

Azimuthal Quantum Number(l) -

For a given value of n, l can have n values ranging from 0 to n – 1, that is, for a given value of n, the possible value of l are : l = 0, 1, 2, ....( n –1)

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$_{24}Cr\rightarrow 1s^{2}\: 2s^{2}\: 2p^{6}\: 3s^{2}\: 3p^{6}\: 3d^{5}\: 4s^{1}$

we know for $p,l=1\: and \: for\: d,l= 2$

$F\! or\; l=1,total\: number\: of \: electrons \: = 12\: \: \left [ 2p^{6}\ and\ 3p^{6} \right ]$

$F\! or\; l=2,total\: number\: of \: electrons \: = 5\: \: \left [ 3d^{5} \right ]$

Option 1)

$12 \: and \: 4$

Incorrect option

Option 2)

$12 \: and \: 5$

Correct option

Option 3)

$16 \: and \: 4$

Incorrect option

Option 4)

$16 \: and \: 5$

Incorrect option

N

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