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  • I have a doubt, kindly clarify. - Atomic Structure - JEE Main

The radius of the second Bohr orbit for hydrogen atom is :

(Planck’s Const. h=6.6262×10−34 Js;

mass of electron=9.1091×10−31 kg;

charge of electron e=1.60210×10−19  C;

permittivity of vacuum \epsilon _{0}  =8.854185×10−12 kg−1m−3A2)

  • Option 1)

    0.529 Å

  • Option 2)

    2.12 Å

  • Option 3)

    1.65 Å

  • Option 4)

    4.76 Å

 

Answers (2)

best_answer

As we learnt in 

Bohr radius of nth orbit -

r_{n}= 0.529 \frac{n^{2}}{z}A^{0}

where Z is atomic number

-

r_{n}= 0.529 \frac{n^{2}}{z}A^{0}

 given that n = 2 and z = 1

r = .529 X 22 / 1 = 2.12 A0 

Hence, the correct option is 2

 


Option 1)

0.529 Å

Incorrect option

Option 2)

2.12 Å

Correct option

Option 3)

1.65 Å

Incorrect option

Option 4)

4.76 Å

Incorrect option

Posted by

prateek

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