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  • I have a doubt, kindly clarify. - Linear Programming - BITSAT

If x_{1}+x_{2} is less than or equal to 500y and y is (0-1), If y is 0, then x_{1}andx_{2} will be

  • Option 1)

    equal to 0

  • Option 2)

    less than 0

  • Option 3)

    > 0

  • Option 4)

    =500

 

Answers (1)

best_answer

As we learnt in 

Corner Point Method -

This method of solving a LPP graphically is based on the principle of extreme points theorem.

-

 

 x_{1}+x_{2}\leq 500y

at \ \ y =0 \ \ \ x_{1}+x_{2}\leq 0

at \ \ y =-1 \ \ \ x_{1}+x_{2}\leq -500

Since \ x_{1}\ \: \: \&\ \: \: x_{2}\geqslant 0

So only  x_{1}=0\ \: \: \&\ \: \: x_{2}=0 satisfies.

 

 


Option 1)

equal to 0

correct

Option 2)

less than 0

Incorrect

Option 3)

> 0

Incorrect

Option 4)

=500

Incorrect

Posted by

Plabita

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