Two very long , straight and insulated wires are kept at 90^{\circ} angle from each other in xy-plane as shown in the figure.

These wires carry current of equal magnitude I, whose directions are shown in the figure. The net magnetic field at point P will be:

 

  • Option 1)

    Zero

  • Option 2)

    -\frac{\mu_{0}I}{2 \pi d}\left (\hat x+\hat y \right )

  • Option 3)

    \frac{+\mu_{0}I}{ \pi d}\left (\hat z \right )

  • Option 4)

    \frac{\mu_{0}I}{2 \pi d}\left (\hat x+\hat y \right )

 

Answers (1)

 

For Infinite Length -

\phi_{1}=\phi_{2}=90^{\circ}

B=\frac{\mu_{o}}{4\pi}\:\frac{2i}{r}\:

- wherein

 

 

B_{1}=\frac{\mu_{0}I}{2y}\hat{k}

B_{2}=\frac{\mu_{0}I}{2y}(-\hat{k})

B=\frac{\mu_{0}I}{2y}-\frac{\mu_{0}I}{2x}=0 \left ( x=y=d \right )


Option 1)

Zero

Option 2)

-\frac{\mu_{0}I}{2 \pi d}\left (\hat x+\hat y \right )

Option 3)

\frac{+\mu_{0}I}{ \pi d}\left (\hat z \right )

Option 4)

\frac{\mu_{0}I}{2 \pi d}\left (\hat x+\hat y \right )

Preparation Products

Knockout JEE Main July 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
Buy Now
Rank Booster JEE Main 2020

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 9999/- ₹ 4999/-
Buy Now
Test Series JEE Main July 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 1999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 17999/- ₹ 11999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 19999/-
Buy Now
Exams
Articles
Questions