Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • I have a doubt, kindly clarify. - Oscillations and Waves - JEE Main-5

A 1\times10^{-20}\: kg particle is vibrating with simple harmonic motion with a period of 1\times10^{-5}\: s and a maximum speed of 1\times10^{3}\: m/s. The maximum displacement of the particle is 

  • Option 1)

    1.59\: mm

  • Option 2)

    1.0 \: m

  • Option 3)

    10\: m

  • Option 4)

    None of these

 

Answers (1)

best_answer

\\*v_{max} = a\omega = a \times \frac{2\pi}{7} \Rightarrow a = \frac{v_{max} \times T}{2\pi}\\*A =\frac{1.00\times 10^{3} \times (1\times 10^{-5})}{2\pi} = 1.59 mm

 

Amplitude -

The maximum displacement of particle from its mean position where it will come to rest or from where it started with zero initial speed.

- wherein

At such point kinetic energy = 0

Potential energy is maximum.

 

 

 


Option 1)

1.59\: mm

This is correct.

Option 2)

1.0 \: m

This is incorrect.

Option 3)

10\: m

This is incorrect.

Option 4)

None of these

This is incorrect.

Posted by

divya.saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’
anam-khan

NIT Puducherry Cut-off 2024: Computer Science and Engineering had highest closing rank last year
anam-khan

JEE Mains: Farmer's son from remote Maharashtra village aces exam

Latest Question