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I have a doubt, kindly clarify. - Oscillations and Waves - JEE Main-5

1\times10^{-20}\: kg particle is vibrating with simple harmonic motion with a period of 1\times10^{-5}\: s and a maximum speed of 1\times10^{3}\: m/s. The maximum displacement of the particle is 

  • Option 1)

    1.59\: mm

  • Option 2)

    1.0 \: m

  • Option 3)

    10\: m

  • Option 4)

    None of these

 
Answers (1)
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\\*v_{max} = a\omega = a \times \frac{2\pi}{7} \Rightarrow a = \frac{v_{max} \times T}{2\pi}\\*A =\frac{1.00\times 10^{3} \times (1\times 10^{-5})}{2\pi} = 1.59 mm

 

Amplitude -

The maximum displacement of particle from its mean position where it will come to rest or from where it started with zero initial speed.

- wherein

At such point kinetic energy = 0

Potential energy is maximum.

 

 

 


Option 1)

1.59\: mm

This is correct.

Option 2)

1.0 \: m

This is incorrect.

Option 3)

10\: m

This is incorrect.

Option 4)

None of these

This is incorrect.

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