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# I have a doubt, kindly clarify. - Oscillations and Waves - JEE Main-5

$1\times10^{-20}\: kg$ particle is vibrating with simple harmonic motion with a period of $1\times10^{-5}\: s$ and a maximum speed of $1\times10^{3}\: m/s$. The maximum displacement of the particle is

• Option 1)

$1.59\: mm$

• Option 2)

$1.0 \: m$

• Option 3)

$10\: m$

• Option 4)

None of these

Answers (1)
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$\\*v_{max} = a\omega = a \times \frac{2\pi}{7} \Rightarrow a = \frac{v_{max} \times T}{2\pi}\\*A =\frac{1.00\times 10^{3} \times (1\times 10^{-5})}{2\pi} = 1.59 mm$

Amplitude -

The maximum displacement of particle from its mean position where it will come to rest or from where it started with zero initial speed.

- wherein

At such point kinetic energy = 0

Potential energy is maximum.

Option 1)

$1.59\: mm$

This is correct.

Option 2)

$1.0 \: m$

This is incorrect.

Option 3)

$10\: m$

This is incorrect.

Option 4)

None of these

This is incorrect.

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