Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • I have a doubt, kindly clarify. - Permutations and combinations - JEE Main

All possible numbers are formed using the digits 1,1,2,2,2,2,3,4,4 taken all at a time. The number of such numbers in which the odd digits occupy even places is :

  • Option 1)

    180

  • Option 2)

    160

  • Option 3)

    175

  • Option 4)

    162

 

Answers (1)

best_answer

1,1,2,2,2,2,3,4,4=9 \; digit

We have total 4 even place and 3 odd digit = 1,1,3

Number of way placing odd digit at even places =^{4}C_{3}\frac{3!}{2!}=4\times3=12

Number of ways placing even digits =\frac{6!}{4!2!}=\frac{6\times5}{2}=15

So total number of ways =12\times15=180


Option 1)

180

Option 2)

160

Option 3)

175

Option 4)

162

Posted by

solutionqc

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question