All possible numbers are formed using the digits 1,1,2,2,2,2,3,4,4 taken all at a time. The number of such numbers in which the odd digits occupy even places is :

  • Option 1)

    180

  • Option 2)

    160

  • Option 3)

    175

  • Option 4)

    162

 

Answers (1)

1,1,2,2,2,2,3,4,4=9 \; digit

We have total 4 even place and 3 odd digit = 1,1,3

Number of way placing odd digit at even places =^{4}C_{3}\frac{3!}{2!}=4\times3=12

Number of ways placing even digits =\frac{6!}{4!2!}=\frac{6\times5}{2}=15

So total number of ways =12\times15=180


Option 1)

180

Option 2)

160

Option 3)

175

Option 4)

162

Preparation Products

Knockout JEE Main Sept 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
Buy Now
Rank Booster JEE Main 2020

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 9999/- ₹ 4999/-
Buy Now
Test Series JEE Main Sept 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 1999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions