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The r.m.s. speed of the molecules of an enclosed gas is x. what will be the r.m.s. speed, if the pressure of the gas is doubled but the temperature is kept constant?

  • Option 1)

    x

  • Option 2)

    \frac{x}{2}

  • Option 3)

    2x

  • Option 4)

    \sqrt x

 

Answers (1)

best_answer

As we learnt in

Root mean square velocity -

V_{rms}= \sqrt{\frac{3RT}{M}}

= \sqrt{\frac{3P}{\rho }}
 

- wherein

R = Universal gas constant

M = molar mass

P = pressure due to gas

\rho = density

 

 V_{rms}   is independent of pressure at a given constant. Hence, final V_{rms} remains the same.


Option 1)

x

This option is correct

Option 2)

\frac{x}{2}

This option is incorrect

Option 3)

2x

This option is incorrect

Option 4)

\sqrt x

This option is incorrect

Posted by

Aadil

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