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I have a doubt, kindly clarify. Which one of the following constitutes a group of the isoelectronic species?

Which one of the following constitutes a group of the isoelectronic species?

  • Option 1)

    N_{2},O{_{2}}^{-},NO^{+},CO

  • Option 2)

    C{_{2}}^{2-},O{_{2}}^{-},CO,NO

  • Option 3)

    NO^{+},C{_{2}}^{2-},CN^{-},N_{2}

  • Option 4)

    CN^{-},N_{2},O{_{2}}^{2-},C{_{2}}^{2-}

 
Answers (2)
204 Views
N neha

As we learnt in

Bond strength -

The energy required to break one mole of bonds of particular type in gaseous state is called bond energy or bond strength.

- wherein

The same amount of energy is released in formation of one mol of particular bond.

 

 

Number of electrons in each species are given below

 

N_{2}= 14\: \: \: \: \: CN^{-}= 14

O{_{2}}^{-}= 17\: \: \: \: \: C{_{2}}^{2-}= 14

NO^{+}= 14\: \: \: \: \: O{_{2}}^{2-}= 18

CO= 14\: \: \: \: \: NO= 15

It is quite evident from the above that NO^{+},C{_{2}}^{2-},CN^{-},N_{2}\: and \: CO are isoelectronic in nature.

Hence NO^{+},C{_{2}}^{2-},CN^{-},N_{2} is correct


Option 1)

N_{2},O{_{2}}^{-},NO^{+},CO

This option is incorrrect

Option 2)

C{_{2}}^{2-},O{_{2}}^{-},CO,NO

This option is incorrrect

Option 3)

NO^{+},C{_{2}}^{2-},CN^{-},N_{2}

This option is corrrect

Option 4)

CN^{-},N_{2},O{_{2}}^{2-},C{_{2}}^{2-}

This option is incorrrect

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