# A particle of mass $'m'$  is moving with speed $'2 v'$ and collides with a mass $'2 m'$ moving with speed $'v'$ in the same direction. After collision , the first mass is stoped completely while the second one splits into two particles each of mass $'m'$, which move at angle $45^{0}$ with respect to the original direction.The speed of each of the moving particle will be : Option 1) $\sqrt{2}v$ Option 2) $2\sqrt{2}v$ Option 3) $v/(2\sqrt{2})$ Option 4) $v/\sqrt{2}$

$\Rightarrow p_{i}=m.2v+2m.v=4mv$

in  $\hat{i}$ direction

$4mv=mv'\cos45^{0}+mv'\cos45^{0}$

$4mv=2mv'\times\frac{1}{\sqrt{2}}$

$\Rightarrow v'= 2\sqrt{2}\:\:V$

Option 1)

$\sqrt{2}v$

Option 2)

$2\sqrt{2}v$

Option 3)

$v/(2\sqrt{2})$

Option 4)

$v/\sqrt{2}$

Exams
Articles
Questions