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# Engineering

A particle of mass 'm'  is moving with speed '2 v' and collides with a mass '2 m' moving with speed 'v' in the same direction. After collision , the first mass is stoped completely while the second one splits into two particles each of mass 'm', which move at angle 45^{0} with respect to the original direction.

The speed of each of the moving particle will be :

  • Option 1)

    \sqrt{2}v

  • Option 2)

    2\sqrt{2}v

  • Option 3)

    v/(2\sqrt{2})

  • Option 4)

    v/\sqrt{2}

 

Answers (1)
S solutionqc

 

\Rightarrow p_{i}=m.2v+2m.v=4mv

 in  \hat{i} direction

4mv=mv'\cos45^{0}+mv'\cos45^{0}

4mv=2mv'\times\frac{1}{\sqrt{2}}

\Rightarrow v'= 2\sqrt{2}\:\:V


Option 1)

\sqrt{2}v

Option 2)

2\sqrt{2}v

Option 3)

v/(2\sqrt{2})

Option 4)

v/\sqrt{2}

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