A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emission is at 680 nm, the other is at

  • Option 1)

    1035 nm

  • Option 2)

    325 nm

  • Option 3)

    743 nm

  • Option 4)

    518 nm

 

Answers (2)
V Vakul

As we learnt in

The energy (E) of a quantum of radiation -

E=hv

Where h is plank’s constant and \nu is frequency

-

 

 

 

 \frac{1}{\lambda } = \frac{1}{\lambda_1 } + \frac{1}{\lambda_2}

\frac{1}{355 } = \frac{1}{680 } + \frac{1}{\lambda_2}

\frac{1}{\lambda_2} = \frac{325}{680 \times 355 }

{\lambda_2} = 743 nm

 


Option 1)

1035 nm

Option 2)

325 nm

Option 3)

743 nm

Option 4)

518 nm

N neha

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