# A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emission is at 680 nm, the other is at Option 1) 1035 nm Option 2) 325 nm Option 3) 743 nm Option 4) 518 nm

N neha
V Vakul

As we learnt in

The energy (E) of a quantum of radiation -

$E=hv$

Where h is plank’s constant and $\nu$ is frequency

-

$\frac{1}{\lambda } = \frac{1}{\lambda_1 } + \frac{1}{\lambda_2}$

$\frac{1}{355 } = \frac{1}{680 } + \frac{1}{\lambda_2}$

$\frac{1}{\lambda_2} = \frac{325}{680 \times 355 }$

${\lambda_2} = 743 nm$

Option 1)

1035 nm

Option 2)

325 nm

Option 3)

743 nm

Option 4)

518 nm

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