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A thin hollow sphere of mass m is completely filled with an ideal liquid of mass m. When the sphere rolls with a velocity v kinetic energy of the system is equal to

 

  • Option 1)

    (1/2) mv^{2}

  • Option 2)

    mv^{2}

  • Option 3)

    (4/3) mv^{2}

  • Option 4)

    (4/5) mv^{2}

 

Answers (1)

best_answer

As we discussed in concept

Kinetic energy of rotation -

K=\frac{1}{2}Iw^{2}

- wherein

I = moment of inertia about axis of rotation

w = angular velocity

 

 E_{trons}=\frac{1}{2}mv^{2}+\frac{1}{2}mv^{2}=mv^{2}

E_{rots}=\frac{1}{2}Iw^{2}= \frac{1}{2} \frac{2}{3}mv^{2}\frac{v^{2}}{r^{2}}

E_{rot}=\frac{1}{3}mv^{2}

K.E of the system

E=mv^{2}+\frac{1}{3}mv^{2} = \frac{4}{3}mv^{2}


Option 1)

(1/2) mv^{2}

This is incorrect option

Option 2)

mv^{2}

This is incorrect option

Option 3)

(4/3) mv^{2}

This is correct option

Option 4)

(4/5) mv^{2}

This is incorrect option

Posted by

prateek

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