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An electric field of 1000 V/m is applied to an electric dipole at angle of 45o . The value of electric dipole moment is 10-29 C.m. What is the potential energy of the electric dipole ?

  • Option 1)

    - 20 x 10-18 J

  • Option 2)

    - 10 x 10-29 J

  • Option 3)

    - 7 x 10-27 J

  • Option 4)

    - 9 x 10-20 J

Answers (1)

best_answer

 

Work done in rotation -

if\; \Theta _{1}= 90^{\circ}\; and \; \Theta _{2}=\Theta

\dpi{100} W=U=-PE\cos \Theta

U=-\vec{P}\cdot \vec{E}

-

U=-\vec{P}\cdot \vec{E}

P= 10^{-29}

\vec{E}=1000v/m

\theta =45

U=-PE\cos \theta

=-(10^{-29}\times 10^{3}\times \frac{1}{\sqrt{2}})

U=-7\times 10^{-27}J

 


Option 1)

- 20 x 10-18 J

Option 2)

- 10 x 10-29 J

Option 3)

- 7 x 10-27 J

Option 4)

- 9 x 10-20 J

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