Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • I need help with An LCR circuit is equivalent to a damped pendulum. In an LCR circuit the capacitor is charged to Q0 and then connected to the L and R as shown below :If a student plots graphs of the square of maximum charge ( Q2Max ) on the capacito

 An LCR circuit is equivalent to a damped pendulum. In an LCR circuit the capacitor is charged to Q0 and then connected to the L and R as shown below :

If a student plots graphs of the square of maximum charge ( Q2Max ) on the capacitor with time(t) for two different values L1 and L2 (L 1>L2) of L then which of the following represents this graph correctly ? (plots are schematic and not drawn to scale)

 

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 

Answers (1)

 

As we learnt in

LR Circuit Voltage -

V_{R}= IR

V_{L}= {I}X_{L}

- wherein

 

 damping constant for a simple pendulum is inversely proportional to m.

Here damping constant is inversely proportional to L.

 q = q_{o} . e ^{-\gamma t}

\therefore \gamma_{1} < \gamma_{2}

\therefore second case will have higher rate of decay & the graph will follow the exponential equation.


Option 1)

This option is correct.

Option 2)

This option is incorrect.

Option 3)

This option is incorrect.

Option 4)

This option is incorrect.

Posted by

Vakul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’
anam-khan

NIT Puducherry Cut-off 2024: Computer Science and Engineering had highest closing rank last year
anam-khan

What after JEE Main results 2024? All you need to know about JEE Adv, CSAB, JoSAA counselling

Latest Question